Question

calcule,caso exista em IR
$\sqrt{100}$
$- \sqrt{10}$
$\sqrt{ - 100}$
$\sqrt[2]{27}$
$\sqrt[3]{ - 27}$
$- \sqrt[3]{ - 27}$
​

Answer 1

Espero ter ajudado.

A

$\sqrt{100}\\\\=10$

B

$-\sqrt{10}\\\\-\sqrt{2\cdot \:5}\\\\-\sqrt{2\cdot \:5}\\\\=-\sqrt{10}$

C

$\sqrt{-100}\\\\=\sqrt{-1}\sqrt{100}\\\\=\sqrt{100}i\\\\=10i$

D

$\sqrt{27}\\\\\sqrt{3^3}\\\\\sqrt{3^2\cdot \:3}\\\\\sqrt{3^2}\sqrt{3}\\\\=3\sqrt{3}$

E

$\sqrt[3]{-27}\\\\-\sqrt[3]{27}\\\\-\sqrt[3]{3^3}\\\\=-3$

F

$-\sqrt[3]{-27}\\\\-\left(-\sqrt[3]{27}\right)\\\\-\left(-\sqrt[3]{3^3}\right)\\\\-\left(-3\right)\\\\=3$