Question

calcule as raízes das equação a) 6x2+12x=0​

Answer 1

Resposta:

6x²+12x=0

$(-b±\sqrt{b²-4.a.c})/2.a$

$(-12±\sqrt{12²-4.6.0})/2.6$

$(-12±\sqrt{144})/12$

$(-12±12)/12$

x1=(-12+12)/12=0

x2=(-12-12)/12=-24/12=-2