Question

calcule as potências:
$( - 1) {}^{4}$

$( - 1) {}^{7}$

$( - 4) {}^{2}$

$( \frac{3}{5} ) {}^{2}$

$( \frac{ - 1}{2} ) {}^{4}$

$( \frac{ - 4}{7} ) {}^{2}$

$( \frac{5}{4} ) {}^{0}$

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Answer 1

Resposta:

Explicação passo a passo:

$(-1)^{4}$ = (-1).(-1).(-1).(-1) = 1

$(-1)^{7}$ = (-1).(-1).(-1).(-1).(-1).(-1).(-1) = -1

$(-4)^{2}$ = (-4).(-4) = 16

$(\frac{3}{5})^{2}$ = $\frac{3^{2} }{5^{2}}$ = $\frac{9}{25}$ = 0,36

$(\frac{-1}{2})^{4}$ = $\frac{-1^{4}}{2^{4}}$ = $\frac{1}{16}$ = 0,0625

$(\frac{-4}{7}) ^{2}$ = $\frac{-4^{2}}{7^{2}}$ = $\frac{16}{49}$ = 0,326

$(\frac{5}{4}) ^{0}$ = 1