Question

calcule as potencias
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Answer 1

${2.3}^{2} = ( \frac{23}{10} )^{2} = \frac{ {23}^{2} }{ {10}^{2} } = \frac{529}{100} = 5.29$

$( { - 5})^{2} = ( - 5) \times ( - 5) = 25$

$( - 2)^{ - 3} = \frac{1}{( - 2)^{3} } = \frac{1}{( - 2) \times ( - 2)\times ( - 2) } = -\frac{1}{ 8} =- 0.125$