Question

calcule as operacoes com Radicais.

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Answer 1

Oie, Td Bom?!

c)

$= 3 \sqrt[3]{2} - 7 \sqrt[3]{2} - 6 \sqrt[3]{2}$

$= (3 - 7 - 6) \sqrt[3]{2}$

$= (3 - 13) \sqrt[3]{2}$

$= - 10 \sqrt[3]{2}$

d)

$= \sqrt{15} \sqrt{6}$

$= \sqrt{15 \: . \: 6}$

$= \sqrt{90}$

$= \sqrt{3 {}^{2} \: . \: 10}$

$= \sqrt{3 {}^{2} } \sqrt{10}$

$=3 \sqrt{10}$

e)

$= 3 \sqrt[5]{6} \: . \: 4 \sqrt[5]{5}$

$= 12 \sqrt[5]{6} \sqrt[5]{5}$

$= 12 \sqrt[5]{6 \: . \: 5}$

$= 12 \sqrt[5]{30}$

f)

$= \sqrt[3]{128} \div \sqrt[3]{2}$

$= \sqrt[3]{128 \div 2}$

$= \sqrt[3]{64}$

$= \sqrt[3]{4 {}^{3} }$

$= 64$

g)

$= \sqrt{8} \div \sqrt{2}$

$= \sqrt{8 \div 2}$

$= \sqrt{4}$

$= \sqrt{2 {}^{2} }$

$= 2$

Att. Makaveli1996

Answer 2

Explicação passo-a-passo:

c)

$\sf 3\sqrt[3]{2}-7\sqrt[3]{2}-6\sqrt[3]{2}$

$\sf =-4\sqrt[3]{2}-6\sqrt[3]{2}$

$\sf =\red{-10\sqrt[3]{2}}$

d)

$\sf \sqrt{15}\cdot\sqrt{6}$

$\sf =\sqrt{90}$

$\sf =\sqrt{9\cdot10}$

$\sf =\red{3\sqrt{10}}$

e)

$\sf 3\sqrt[5]{6}\cdot4\sqrt[5]{5}$

$\sf =3\cdot4\cdot\sqrt[5]{6}\cdot\sqrt[5]{5}$

$\sf =\red{12\sqrt[5]{30}}$

f)

$\sf \sqrt[3]{128}\div\sqrt[3]{2}$

$\sf =\sqrt[3]{64}$

$\sf =\sqrt[3]{4^3}$

$\sf =\red{4}$

g)

$\sf \sqrt{8}\div\sqrt{2}$

$\sf =\sqrt{4}$

$\sf =\sqrt{2^2}$

$\sf =\red{2}$