Question

Calcule as massas moleculares dos compostos:
A) NaOh
B) C6H12O6
C) CaCO3
D) KOH
E) BaSO4
F) C12H22O11
G) H2S04

Answer 1

A) NaOH = 23 + 16+1
                = 40 g/mol

B) C6H12O6 = 12*6 + 1.12+ 16*6
                     = 72 + 12+ 96
                     = 84+96
                     = 180 g/mol
 
C) CaCO3
= 40 + 12+ 16*3
= 40 + 12+ 48
= 100 g/mol

D) KOH
     = 39 + 16 + 1
     = 56 g/mol

E) BaSO4
  = 137 + 32 + 16*4
 = 137 + 32 + 64
 = 233g/mol

F) C12H22O11



   = 12*12 +1.222+ 16.11
   = 144 + 22 + 176
= 342 g/mol

G)H2SO4
 = 1.2 + 32 + 16.4
 = 2 + 32 + 64
= 98 g/mol

I hope I helped you