Question

Calcule as massas molares dos compostos abaixo: (Dados - Massas atômicas: C=12, H=1, O=16, K=39, Fe= 56, N=14) *

a)C6H12O6 (glicose)
b) K4Fe(CN)6 (ferrocianeto de potássio)
c) C12H22O11 (sacarose)​

Answer 1

Resposta:

a) 1,08.10^26 g/mol

b) 2,208.10^26 g/mol

c) 2,052.10^26 g/mol

Explicação:

a)12.6+12.1+6.16=84+96 = 180g

180. 6.10^23 = 1080.10^23 = 1,08. 10^26 g/mol

b)39.4+56.1+12.6+14.6=156+56+72+84= 240+128 = 368g

368.6.10^23 = 2208.10^23 g/mol

=2,208.10^26 g/mol

c) 12.12+22.1+16.11=342g

342.6.10^23 =2052.10^23= 2,052.10^26 g/mol