Question

calcule as equações do 2 grau, por Bháskara.
a)
$x \: ( \: x - 2 \: ) = 2 \: ( \: x + 6) =$
b)
${x}^{2} - 7x + 10 = 0$

Answer 1

a)

x.(x - 2) = 2.(x + 6)

x.x - 2.x = 2.x + 2.6

x² - 2x = 2x + 12

x² - 2x - 2x - 12 = 0

x² - 4x - 12 = 0

Δ = b² - 4.a.c

Δ = -4² - 4 . 1 . -12

Δ = 16 - 4. 1 . -12

Δ = 64

Há 2 raízes reais.

x = (-b +- √Δ)/2a

x' = (--4 + √64)/2.1

x'' = (--4 - √64)/2.1

x' = 12 / 2

x'' = -4 / 2

x' = 6

x'' = -2

b)

x² - 7x + 10 = 0

Δ = b² - 4.a.c

Δ = -7² - 4 . 1 . 10

Δ = 49 - 4. 1 . 10

Δ = 9

Há 2 raízes reais.

x = (-b +- √Δ)/2a

x' = (--7 + √9)/2.1

x'' = (--7 - √9)/2.1

x' = 10 / 2

x'' = 4 / 2

x' = 5

x'' = 2

Answer 2

X(X-2)=2(X +6)

C

X²-2x=2x+12

X²-2x -2x -12=0

x² -4x -12=0

Δ=(-4)²-4( (1(-12)

Δ=16 +48

Δ=64

+4+-√64/2

+4+-8/2

X,=4+8/2

X,=12/2

X,= 6

X=4-8/2

X,,=- 4/2

X,,= -2

X²

-b+-√Δ/2a

X²-7x +10=0

Δ= (-7)²-4.1.10

Δ=49 -40

Δ=9

X=+7+-√9/2

X= +7 +-3/2

X=+7+3/2

X=10/2

X,=5

X=+7-3/2

X,,=4/2

X,,=2