Question

calcule as adições$\frac{3}{x} - \frac{2x}{y} + \frac{1}{y} =$:

Answer 1

$\frac{a}{b}-\frac{c}{d}=\frac{ad-bc}{bd}$

Sendo assim,

$\frac{3}{x}-\frac{2x}{y}=\frac{3y-2x^2}{xy} +\frac{1}{y}=\frac{3y^2-2x^2y+xy}{xy^2}$

Agora vamos simplificar.

$\frac{3y^2-2x^2y+xy}{xy^2}=\frac{y.(3y-2x^2+x)}{xy^2}=\frac{3y-2x^2+x}{xy}$