Question

calcule a soma dos seis primeiros termos da PG 1/81 1/27 1/9 ?

Answer 1

sn=a1.(q^n-1)/q-1                       razao(q)=1/27:1/81=1/27x81/1=81/27=3
Sn=1/81.(3^6-1)3-1
Sn=1/81.(729-1)/2
Sn=1/81.728/2

sn=728/81:2
sn=58968/2
sn=29484