Question

Calcule a soma dos seis primeiros termos da P.G. (1/32, 1/16, 1/8…)

Answer 1

a1 = 1/32

a2 = 1/16

q = 1/16 : 1/32 ou  1/16 * 32/1 =  32/16 = 2 ****

S6 = a1 * ( q^6   -  1)/ ( q - 1)

S6 = 1/32 ( 2^6   -  1)/ ( 2 - 1)

S6 = 1/32 ( 64 - 1 )/1

S6 = 1/32 * 63/1 =  63/32 = 2 ***** resposta