Question

Calcule a soma dos múltiplos de 12, compreendidos entre 50 e 200.

Answer 1

a1=60
an=192
razão=12
n=?

an=a1+(n-1).r
192=60+(n-1).12
192=60+12n-12
192+12-60=12n
144=12n
n=144/12
n=12


sn=(a1+an).n/2
s12=(60+192).12/2
s12=252.12/2
s12=3024/2
s12=1512