Question

(Calcule a soma) dos catetos sabendo que AB = 10 e COS α = 3/5.

Answer 1

cos a = AC / 10
3/5 = AC /10
5AC = 30
AC = 6 ✓

BC² + AC² = 10²
BC² + 6² = 100
BC² = 64
BC = 8 ✓

==> AC + BC = 6 + 8 = 14 ✓