Question

calcule a soma dos 6 primeiros termos da p.g (4,2,1,1/2,...)

Answer 1

Boa tarde

PG

u1 = 4

u2 = 2

q = u2/u1 = 2/4 = 1/2

soma

Sn = u1*(1 - q^n)/(1 - q)

S6 = 4*(1 - (1/2)^6)/(1 - 1/2)

S6 = 4*(64/64 - 1/64)/(1/2)

S6 = 8*63/64

S6 = 63/8