Matemática, perguntado por nayudsonoup6c7, 1 ano atrás

calcule a simplifique o resultado quando for possivel ;
a)2/5+1/3
b)7/9-1/6
c)5/8+7/12
d)1/4-1/8
e)1/3+1/6+1/12
f)4/5+1/2-5/8

Soluções para a tarefa

Respondido por ProfAmaral
3
a)\ \frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{6+5}{15}=\frac{11}{15}\\
\\b)\ \frac{7}{9}-\frac{1}{6}=\frac{14}{18}-\frac{3}{18}=\frac{14-3}{18}=\frac{11}{18}\\
\\c)\ \frac{5}{8}+\frac{7}{12}=\frac{15}{24}+\frac{14}{24}=\frac{15+14}{48}=\frac{29}{24}\\
\\d)\ \frac{1}{4}-\frac{1}{8}=\frac{2}{8}-\frac{1}{8}=\frac{2-1}{8}=\frac{1}{8}\\

\\e)\ \frac{1}{3}+\frac{1}{6}+\frac{1}{12}=\frac{4}{12}+\frac{2}{12}+\frac{1}{12}=\frac{4+2+1}{12}=\frac{7}{12}\\
\\f)\ \frac{4}{5}+\frac{1}{2}-\frac{5}{8}=\frac{32}{40}+\frac{20}{40}-\frac{25}{40}=\frac{32+20-25}{40}=\frac{27}{40}\\

nayudsonoup6c7: obg
ProfAmaral: Disponha!
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