Question

calcule a potência (1_i)17

Answer 1

(1+i)^17...........=> (1+i)² = 1+2i -1 = 2i 

(1+i)^16. (1+i)^1 

[(1+i)²]^8. (1+i) 

[2i]^8. (1+i) 

2^8.i^8. (1+i)...........=> i^8 = (i²)^4 = (-1)^4 = 1 

256.1. (1+i) 

256.(1+i) ....ou......256+256i