Question

Calcule a medida do X no triângulo a seguir: ​

Answer 1

$\large \text{ \sf{ x = 2 \sqrt{5} } }$

Explicação:

$\large \text{ \sf{x {}^{2} = ( \sqrt{10} ) {}^{2} + ( \sqrt{10}) {}^{2} } }$

$\large \text{ \sf{x {}^{2} = 10 + 10 } }$

$\large \text{ \sf{x {}^{2} = 20 } }$

$\large \text{ \sf{x = \sqrt{20} } }$

$\large \text{ \sf{ x = 2 \sqrt{5} } }$

Answer 2

$\large\boxed{\begin{array}{l} \rm{x {}^{2} = ( \sqrt{10} ) {}^{2} + ( \sqrt{10} ) {}^{2} } \\ \rm{x {}^{2} = 10 + 10} \\ \rm{x {}^{2} = 20} \\ \rm{x = \sqrt{20} } \\ \huge\boxed{\boxed{\boxed{\boxed{\rm{x = 2 \sqrt{5} }}}}}\end{array}}$