Question

calcule a media harmonica simples de 2,6,8

Answer 1

$\boxed{\mathbf{MH=\dfrac{n}{\dfrac{1}{x_1}+\dfrac{1}{x_2}+\dfrac{1}{x_3}+\dots+\dfrac{1}{x_n}}}}\\\\\\ \mathrm{(x_1;x_2;x_3)=(2;6;8)\ \to\ n=3}\\\\ \mathrm{MH=\dfrac{3}{\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{8}}=\dfrac{3}{\dfrac{12+4+3}{24}}=\dfrac{3}{\dfrac{19}{24}}=}\\\\\\ \mathrm{=3.\dfrac{24}{19}=\dfrac{72}{19}\ \to\ \boxed{\mathbf{MH\approx3,789473684}}}$