Question

Calcule a média dos números:
a) 3,9,12
b)12,6,8,13

Answer 1

a) $m_a= \frac{3+6+12}{3} \\\\ m_a= \frac{21}{3} \\\\ m_a=7$
    $m_g= \sqrt{3*6*9} \\ m_g= \sqrt{162} \\ m_g=9 \sqrt{2}$

b) $m_a= \frac{6+8+12+13}{4} \\\\ m_a= \frac{39}{4} \\\\ m_a=9,75$
    $m_g= \sqrt{6*8*12*13} \\ m_g= \sqrt{7488}\\ m_g= 24 \sqrt{13}$

Answer 2

a)
(3+9+12)/3=
24/3=
8
Resposta:  8

b)
(12+6+8+13)/4=
39/4=
9,75
Resposta:  9,75