Question

calcule a integral impropria | 1/x³ dx ? passo a passo por favor !
 
 
 
 

 
 
 
 
 

Answer 1

$\displaystyle \int_{a}^{b}\frac{1}{x^3}dx=\left.\left(-\frac{1}{2x^2}\right)\right|_{a}^{b}\\ \\ \\ \boxed{\int_{a}^{b}\frac{1}{x^3}dx=\lim\limits_{x\to b^-} \left(-\frac{1}{2x^2}\right) - \lim\limits_{x\to a^+} \left(-\frac{1}{2x^2}\right)}$