Question

calcule a area de um triangulo escaleno com os lados medindo 10m,12m, e 6m​

Answer 1

Resposta:

(2.

13

)

2

=4

2

+y

2

4.13=16+y

2

52=16+y

2

\begin{gathered} {y}^{2} = 52 - 16 \\ \\ {y}^{2} = 36 \\ \\ y = \sqrt{36} \\ \\ \end{gathered}

y

2

=52−16

y

2

=36

y=

36

y = 6y=6

\begin{gathered} {10}^{2} = {6}^{2} + {x}^{2} \\ 100 = 36 + {x}^{2} \\ {x}^{2} = 100 - 36 \\ {x}^{2} = 64 \\ x = \sqrt{64} \end{gathered}

10

2

=6

2

+x

2

100=36+x

2

x

2

=100−36

x

2

=64

x=

64

x = 8x=8

\begin{gathered}a = \frac{b.h}{2} \\ \end{gathered}

a=

2

b.h

\begin{gathered}a = \frac{11.6}{2} \\ \end{gathered}

a=

2

11.6

\begin{gathered}a = \frac{66}{2} \\ \end{gathered}

a=

2

66

a = 33m {}^{2}a=33m

2