Question

calcule a altura de um triângulo equilátero cujo lado mede 5 cm​

Answer 1

Resposta:

${5}^{2} = 2.5 {}^{2} + h {}^{2} \\ \\ 25 = ( \frac{5}{2}) {}^{2} + h {}^{2} \\ \\ 25 = \: \frac{25}{4} + {h}^{2} \\ \\ 100 = 25 + 4 {h}^{2} \\ \\ 4 {h}^{2} = 75 \\ \\ {h}^{2} = \frac{75}{4} \\ \\ h = \frac{5 \sqrt{3} }{2} \: cm.$