Question

Calcule:
a) 3(3x^5 + x)(x + 1)
b) (x^2 − 4) ÷ (x − 2)
c) (4x^2 + 1)(x − 3)
d) (x^2 + 9x + 14)(x + 2)

Answer 1

Resposta:

a) 9x^6 + 9x^5 + 3x^2 + 3x

b) x + 2

c) 4x^3 - 12x^2 + x - 3

d) x^3 + 11x^2 + 32x + 28

Explicação passo-a-passo:

a) 3.(3x^5 + x).(x + 1)=

3.(3x^6 + 3x^5 + x^2 +x) =

9x^6 + 9x^5 + 3x^2 + 3x

b) (x^2 - 4) / (x - 2) = [(x + 2).(x - 2)] / (x - 2) = x + 2

"Obs.: Diferença de quadrados: (x^2 - 4) = (x + 2).(x - 2)"

c) (4x^2 + 1).(x - 3) = 4x^3 - 12x^2 + x -3

d) (x^2 + 9x + 14) . (x + 2) = x^3 + 2x^2 + 9x^2 + 18x + 14x + 28 =

= x^3 +11x^2 + 32x + 28