Question

calcule: 2^-4 -2^2 e (4^-1 + 2^-3)^-1

Answer 1

Boa tarde!

$2 ^{-4} = \frac{1}{2^4}= \frac{1}{16}\\\\-2^2=4\\\\(4^{-1}+2^{-3})^{-1}= (\frac{1}{4}+ \frac{1}{2^3})^{-1}= (\frac{1}{4} + \frac{1}{8} )^{-1}=( \frac{2+1}{8})^{-1}=( \frac{3}{8}) ^{-1}= \frac{8}{3}$

Abraço!