Question

Calcule:
(2∙3,1)+(11+3)−23 +(7÷5) 52 23
a) 4 b) 2,3 c) 6,2 d) 8

Answer 1

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$\boxed{ \color{green} \boxed{{ 4 }}}$

Passo a Passo.

$(2 \times 3.1) + ( \frac{11}{5} + \frac{3}{2} ) - {2}^{3} + ( \frac{7}{2} \div \frac{5}{3} )$

$6.2 + ( \frac{11}{5} + \frac{3}{2} ) - {2}^{3} + ( \frac{7}{2} \div \frac{5}{3} )$

$6.2 + \frac{22 + 15}{10} - {2}^{3} + ( \frac{7}{2} \div \frac{5}{3} )$

$6.2 + \frac{37}{10} - {2}^{3} + ( \frac{7}{2} \div \frac{5}{3} )$

$6.2 + \frac{37}{10} - 8 + ( \frac{7}{2} \div \frac{5}{3} )$

$6.2 + \frac{37}{10} - 8 + ( \frac{7}{2} \times \frac{3}{5} )$

$\frac{62}{10} + \frac{37}{10} - 8 + ( \frac{7}{2} \times \frac{3}{5} )$

$\frac{\cancel{ 62 } \div 2}{\cancel{ 10 } \div 2} + \frac{37}{10} - 8 + ( \frac{7}{2} \times \frac{3}{5} )$

$\frac{31}{5} + \frac{37}{10} - 8 + ( \frac{7}{2} \times \frac{3}{5} )$

$\frac{31}{5} + \frac{37}{10} - 8 + \frac{7 \times 3}{2 \times 5}$

$\frac{31}{5} + \frac{37}{10} - 8 + \frac{21}{10}$

$\frac{31}{5} + \frac{37 + 21}{10} - 8$

$\frac{31}{5} + \frac{58}{10} - 8$

$\frac{31}{5} + \frac{\cancel{ 58 } \div 2}{\cancel{ 10 } \div 2} - 8$

$\frac{31}{5 } + \frac{29}{5} - 8$

$\frac{31 + 29}{5} - 8$

$\frac{60}{5} - 8$

$\frac{\cancel{ 60 } \div 5}{\cancel{ 5 } \div 5}$

$12 - 8$

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