Question

Calcule (1/3)^-10 x 27^-3 + (0,2)^-4 x 25^-2 +(64^-1/9)^-3.

Answer 1

$( \frac{1}{3} ) {}^{ - 10} \times {27}^{ - 3} + (0.2) {}^{ - 4} \times {25}^{ - 2} + (64 {}^{ - \frac{1}{9} } ) {}^{ - 3} \\ {3}^{10} \times ( {3}^{3} ) {}^{ - 3} + {5}^{4} \times ( {5}^{2} ) {}^{ - 2} + {64}^{ \frac{1}{3} } \\ {3}^{10} \times {3}^{ - 9} + {5}^{4} \times {5}^{ - 4} + ( {2}^{6} ) {}^{ \frac{1}{3} } \\ 3 + 1 + {2}^{2} \\ 3 + 1 + 4 \\ 8$