Question

Calcular

${2^{n+4}-2.2^n\over2.2^{n+3}}=$

Answer 1

$\frac{ {2}^{n + 4} - 2 \times {2}^{n} }{2 \times {2}^{n + 3} } =$

$\frac{ {2}^{n + 4} }{2 \times {2}^{n + 3} } - \frac{2 \times {2}^{n} }{2 \times {2}^{n + 3} } =$

$\frac{ {2}^{n + 4} }{ {2}^{n + 4} } - \frac{ {2}^{n} }{ {2}^{n + 3} } =$

$1 - \frac{1}{ {2}^{3} } =$

$1 - 0.125 = 0.875$

Answer 2

Explicação passo-a-passo:

$Desmembrar\\ \\ {2^n.2^4-2.2^n\over2.2^n.2^3}}=\\ \\ fatorar~com~~2^n~~como~~fator~~comum\\ \\ {2^n(2^4-2)\over2^n(2.2^3)}=\\ \\ Cancelar~~2^n\\ \\ {(16-2)\over(2.8)}={14\over16}={7\over8}$