Question

Calcular o limite:
lim x³-1 / x²-3x+2
x--> 1

Answer 1

Oi. Resposta é -3 

$\lim_{n \to 1} \frac{x^3-1}{x^2-3x+2} \\ \\ \lim_{n \to 1} \frac{(x-1)(x^2+x+1)}{(x-1)(x-2)} \\ \\ \lim_{x \to 1} \frac{x^2+x+1}{x-2} \\ \\ \lim_{x \to 1} \frac{1^2+1+1}{1-2} \\ \\ \lim_{x \to 1} \frac{3}{-1} \\ \\ \lim_{x \to 1} -3$