Question

Calcular log2 (3x² +5) = 5

Answer 1

$log_2(3x^2+5)=5 \rightarrow 3x^2+5=2^5 \\ \\ 3x^2+5=32 \\ \\ 3x^2=32-5 \\ \\ 3x^2=33 \\ \\ x^2=11 \\ \\ x=+-\sqrt{11}$