Question

calcua distância entre a e b nos casos a=5,6 e b=1,3

Answer 1

$A=(5,6) \qquad B=(1,3)\\d_{AB}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d_{AB}=\sqrt{(1-5)^2+(3-6)^2}\\d_{AB}=\sqrt{(-4)^2+(-3)^2}\\d_{AB}=\sqrt{16+9}\\d_{AB}=\sqrt{25}\\d_{AB}=5$

Espero ter sido util