Question

Boa noite Questão sobre Geometria plana

Answer 1

$\displaystyle \text{En el tri\'angulo }ABC\\ \\ R^2=(x-R) ^2+\left(\frac{x}{2}\right)^2\\ \\ R^2=x^2-2xR+R^2+\frac{x^2}{4}\\ \\ 2xR=\frac{5x^2}{4}\\ \\ \boxed{R=\frac{5x}{8}}$