Question

bhaskara 2ª grau

x² – 23x + 22 = 0​

Answer 1

$x^2-23x+22=0\Longrightarrow a=1,\ b=-23,\ c=22.$

$\boxed{x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}}$

$\Longrightarrow x=\dfrac{-(-23)\pm\sqrt{(-23)^2-4(1)(22)}}{2(1)}$

$\Longrightarrow x=\dfrac{23\pm\sqrt{441}}{2}=\dfrac{23\pm21}{2}$

$\Longrightarrow\boxed{x=1}\ \text{ou}\ \boxed{x=22}$