Question

baskara;
a]x2-8x+14=0

Answer 1

x²-8x+14=0

a=1, b=-8, c=14

Δ=b²-4.a.c
Δ=(-8)²-4.1.14
Δ=64-56
Δ=8

8 | 2
4 | 2
2 | 2
 1
√8 = √2².√2 = 2√2

x=(-b+-√Δ)/2.a
x=(-(-8)+-√8)/2.1
x=(8+-2√2)/2
x'=(8+2√2)/2 = 2(4+√2)/2 = 4+√2
x"=(8-2√2)/2 = 2(4-√2)/2 = 4-√2

Solução: {4-√2; 4+√2}