Question

b) (6x₄y₂ - 6x₃y₂ + 6x₂y₂) : (6x₂y₂)
C) (3a₃b₃ - 3a₂b₄ + 3a₂b₃) : (3a₂b₃)

URGENTE

Answer 1

$\frac{6 {x}^{4} {y}^{2} - 6 {x}^{3} {y}^{2} + 6 {x}^{2} {y}^{2}}{6 {x}^{2} {y}^{2}} = \\ \\ {x}^{2} - x + 1$

$\frac{3 {a}^{3} {b}^{3} -3 {a}^{2} {b}^{4} + 3 {a}^{2} {b}^{3}}{3 {a}^{2} {b}^{3}} = \\ \\ a - b + 1$

Answer 2

Oie, Td Bom?!

a)

$\frac{6x {}^{4}y {}^{2} - 6x {}^{3} y {}^{2} + 6x {}^{2} y {}^{2} }{6x {}^{2}y {}^{2} }$

$\frac{6x {}^{2}y {}^{2} \: . \: (x {}^{2} - x + 1) }{6x {}^{2} y {}^{2} }$

$\frac{x {}^{2} y {}^{2} \: . \: (x {}^{2} - x + 1)}{x {}^{2}y {}^{2} }$

$\frac{y {}^{2} \: . \: (x {}^{2} - x + 1)}{y {}^{2} }$

$x {}^{2} - x + 1$

b)

$\frac{3a {}^{3} b {}^{3} - 3a {}^{2}b {}^{4} + 3a {}^{2} b {}^{3} }{3a {}^{2} b {}^{3} }$

$\frac{3a {}^{2}b {}^{3} \: . \: (a - b + 1) }{3a {}^{2}b {}^{3} }$

$\frac{a {}^{2}b {}^{3} \: . \: (a - b + 1) }{a {}^{2} b {}^{3} }$

$\frac{b {}^{3} \: . \: (a - b + 1)}{b {}^{3} }$

$a - b + 1$

Att. Makaveli1996