Question

ATIVIDADES DE FIXAÇÃO.
1) Efetue as multiplicações de monômios indicadas abaixo:
a)( a b )× ( - 2 a² ) =
b)( - 3 m² ) × ( m x ) =
c) ( - 6 a b² ) × ( a² b ) =
d)( 5 m²y ) × ( - m² ) =
e) ( - 7 a4 y ) × ( - y3 ) × (a3 y) =
f) ( 2 a²b ) × ( - a b ) × (- a² ) =

2 ) Efetue as divisões dos seguintes monômios:
a ) ( - 8 a3 x² ) ÷ ( 2 a²x ) =
b ) ( 16 a m x²) ÷ ( - 8 a x ) =
c ) ( - 12 a b² ) ÷ (6 a b ) =
d) ( 9 a4 x² ) ÷ ( 3 a² x² ) =
e ) (- 14 a²b ) ÷ ( 7a 3b² ) =
f ) ( 9axy) ÷ ( - 9a 3x² ) =
e ) ( 12xm3 ) ÷ ( - 2 x m4 ) =

Answer 1

Oie, Td Bom?!

1.

a)

$=(ab) \: . \: ( - 2a {}^{2} )$

$= - ab \: . \: 2a {}^{2}$

$= - 2a {}^{3} b$

b)

$= ( - 3m {}^{2} ) \: . \: (mx)$

$= - 3m {}^{2} \: . \: mx$

$= - 3m {}^{3} x$

c)

$= ( - 6ab {}^{2} ) \: . \: (a {}^{2} b)$

$= - 6ab {}^{2} a {}^{2} b$

$= - 6a {}^{3} b {}^{3}$

d)

$= (5m {}^{2} y) \: . \: ( - m {}^{2} )$

$= - 5m {}^{2} ym {}^{2}$

$= - 5m {}^{4} y$

e)

$= ( - 7a {}^{4} y) \: . \: ( - y {}^{3} ) \: . \: (a {}^{3} y)$

$= 7a {}^{4} y \: . \: y {}^{3} a {}^{3} y$

$= 7a {}^{7} y {}^{5}$

f)

$= (2a {}^{2} b) \: . \: ( - ab) \: . \: ( - a {}^{2} )$

$= 2a {}^{2} baba {}^{2}$

$= 2a {}^{5} b {}^{2}$

2.

a)

$\frac{ - 8a {}^{3}x {}^{2} }{2a {}^{2}x } = \frac{ - 4x {}^{3}x {}^{2} }{a {}^{2} x} = \frac{ - 4ax {}^{2} }{x} = - 4ax$

b)

$\frac{16amx {}^{2} }{ - 8ax} = \frac{16mx {}^{2} }{ - 8x} = \frac{ - 2mx {}^{2} }{x} = - 2mx$

c)

$\frac{ - 12ab {}^{2} }{6ab} = \frac{ - 12b {}^{2} }{6b} = \frac{ - 2b {}^{2} }{b} = - 2b$

d)

$\frac{9a {}^{4} x {}^{2} }{3a {}^{2} x {}^{2} } = \frac{9a {}^{4} }{3a {}^{2} } = \frac{3a {}^{4} }{a {}^{2} } = 3a {}^{2}$

e)

$\frac{ - 14a {}^{2}b }{7a {}^{3} b {}^{2} } = \frac{ - 2a {}^{2} b}{a {}^{3}b {}^{2} } = \frac{ - 2ab}{ab {}^{2} } = \frac{ - 2}{ab} = - \frac{2}{ab}$

f)

$\frac{9axy}{ - 9a {}^{3} x {}^{2} } = \frac{ - axy}{a {}^{3} x {}^{2} } = \frac{ - xy}{a {}^{2}x {}^{2} } = \frac{ - y}{a {}^{2}x } = - \frac{y}{a {}^{2} x}$

g)

$\frac{12xm {}^{3} }{ - 2x m{}^{4} } = \frac{12m {}^{3} }{ - 2m {}^{4} } = \frac{ - 6m {}^{3} }{m {}^{4} } = \frac{ - 6}{m} = - \frac{6}{m}$

Att. Makaveli1996