Question

as raízes da equação 6x2 -13x+6=0

Answer 1

6x² -13x +6 = 0
Δ= b² -4ac 
Δ= (-13)² -4.6.6
Δ= 169 - 144
Δ= 25

x= -b +/- √Δ / 2a
x= -(-13) +/- √25 / 2.6
x'= 13 + 5 / 12
x'= 18 /12 (simplificando por 6)
x'= 3/2

x''= 13 -5 / 12
x''= 8/12 (simplificando por 4)
x''= 2/3

Bons estudos!

Answer 2

$6x^2 -13x+6=0\\\\ a=6;b=-13;c=6\\\\\\ \Delta=b^2-4ac\to \Delta=(-13)^2-4*6*6\to \Delta=169-144\to \Delta=25\\\\\\ x= \frac{-b+- \sqrt{ \Delta } }{2a} \to x= \frac{-(-13)+- \sqrt{ 25} }{2*6} \to x= \frac{13+- 5}{12} \to \\\\\\ x'= \frac{13+ 5}{12} \to x'= \frac{18}{12} \to x'= \frac{3}{2} \\\\\\ x''= \frac{13- 5}{12} \to x''= \frac{8}{12} \to x''= \frac{2}{3}\\\\\\\\ S=(\frac{2}{3};\frac{3}{2})$