As coordenadas do vértice da função y=x² -4x + 4 são :
a) ( -1, 4)
b) ( 2, 0)
c) ( -1, 1 )
d) ( 1, 0 )
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Solução!



Boa noite!
Bons estudos!
Solução!
Boa noite!
Bons estudos!
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