Question

Aplique a formula de Bhaskara: 
a)x²-5x+6=

Answer 1

A Resposta segue em anexo ok

Answer 2

$x^2 \ - \ 5x \ + \ 6 \ = \ 0 \\ \\ a \ = 1 \ \ \ \ \ \ \ b \ = \ - \ 5 \ \ \ \ \ \ \ c \ = \ 6 \\ \\ \Delta \ = b^2 \ - \ 4 \ * \ a \ * \ c \\ \\ \Delta \ = \ (- \ 5)^2 \ - \ 4 \ * \ 1 \ * \ 6 \\ \\ \Delta \ = \ 25 \ - \ 24 \\ \\ \Delta \ = \ 1 \\ \\ x \ = \ \frac{- \ b \ \pm \sqrt \ {\Delta}}{2 \ * \ a}$

$x \ = \ \frac{- \ (- \ 5) \ \pm \sqrt \ {1}}{2 \ * \ 1} \\ \\ x \ = \ \frac{ 5 \ \pm 1}{2} \\ \\ x' \ = \ (5 \ + \ 1) \ \div \ 2 \\ \\ x' \ = \ 6 \ \div \ 2 \\ \\ x' \ = \ 3 \\ \\ x'' \ = \ (5 \ - \ 1) \ \div \ 2 \\ \\ x'' \ = \ 4 \ \div \ 2$

$x'' \ = \ 2 \\ \\ S: \ \{3; \ 2\}$