Question

Aplicando baskara resolva x²=x+12

Answer 1

Olá!

x² = x + 12

x² - x - 12 = 0

a = 1

b = (- 1)

c = (- 12)

∆ = b² - 4ac

∆ = (- 1)² - 4 · 1 · (- 12)

∆ = 1 + 48

∆ = 49

x = - b ± √∆ /2a

x = - (- 1) ± √49 /2 · 1

x = 1 ± 7 /2

x¹ = 1 + 7/2 = 8/2 = 4

x² = 1 - 7/2 = - 6/2 = - 3

S = {- 3, 4}

Espero ter ajudado! :)

Answer 2

Resposta:

x = 4 ou x =-3

Explicação passo-a-passo:

x²=x+12

x² - x -12 =0 (nesse caso a = 1, b = -1 e c = -12)

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x1=\frac{-\left(-1\right)+\sqrt{\left(-1\right)^2-4\cdot \:1\left(-12\right)}}{2\cdot \:1}=\quad 4$

$x2=\frac{-\left(-1\right)-\sqrt{\left(-1\right)^2-4\cdot \:1\left(-12\right)}}{2\cdot \:1}=\quad -3$