Question

Aplicando as relaçõemitricas no triângulo retangulo abaixo sendo que m=2. N=4

Answer 1

$\large\boxed{\begin{array}{l}\sf h^2=m\cdot n\\\sf h^2=4\cdot2\\\sf h=\sqrt{4\cdot2}=2\sqrt{2} \\\sf a=4+2=6\\\sf c^2=a\cdot n\\\sf c^2=6\cdot4\\\sf c=\sqrt{6\cdot4}=2\sqrt{6}\\\sf a\cdot h=b\cdot c\implies b=\dfrac{a\cdot h}{c}\\\\\sf b=\dfrac{6\cdot2\sqrt{2}}{2\sqrt{6}}=\dfrac{12\sqrt{12}}{2\cdot6}=\dfrac{12\cdot2\sqrt{3}}{12}=2\sqrt{3}\end{array}}$