Question

aplicando a definição calcule: (funções exponenciais)

a) -(-2)-³ =

b) -(-1/2)-⁴ =

c) -(1/6)-³ =

d) -(-3/2)-³ =

Answer 1

$a) \ -(-2)^{-3}=-(\frac{1}{-2})^3=-(\frac{1}{-8})=\frac{1}{8}\\ \\ b) \ -(-\frac{1}{2})^{-4}=-(-2)^4=-16\\ \\ c) \ -(\frac{1}{6})^{-3}=-(6)^3=-216\\ \\ d) \ -(-\frac{3}{2})^{-3}=-(-\frac{2}{3})^3=-(-\frac{8}{27})=\frac{8}{27}$

Answer 2

$a^{-n}}=\left(\dfrac{1}{a}\right)^{n}=\dfrac{1}{a^n}$.

a) $-(-2)^{-3}=\dfrac{1}{(-2)^3}=-\left(\dfrac{1}{-8}\right)=\dfrac{1}{8}$.

b) $-\left(-\dfrac{1}{2}\right)^{-4}=-(-2)^4=-16$.

c) $-\left(\dfrac{1}{6}\right)^{-3}=-6^3=-216$.

d) $-\left(-\dfrac{3}{2}\right)^{-3}=-\left(-\dfrac{2}{3}\right)^3=-\left(-\dfrac{8}{27}\right)=\dfrac{8}{27}$.