Question

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Como se calcula o exercicio 2e 3? Responda o mais rápido possível... Obg

Answer 1

Do enunciado:
$a=2,34*10^{23}\\ b=1,17*10^{-9}\\ c = 4,8*10^{20}\\ d=6,4*10^{-12}$

Exercício 2:
$\frac{a}{b} - \frac{c}{d}= \frac{2,34.10^{23}}{1,17.10^{-9}}- \frac{4,8.10^{20}}{6,4.10^{-12}} \\ \frac{2,34.10^{23}}{1,17.10^{-9}} = 2*10^{23-(-9)}=2*10^{32}\\ \frac{4,8.10^{20}}{6,4.10^{-12}}=0,75*10^{20-(-12)}=0,75*10^{32}\\ \frac{a}{b}- \frac{c}{d} =2*10^{32} - 0,75*10^{32}=1,25*10^{32}$

Exercício 3:
$c *d = 4,8*10^{20}*6,4*10^{-12}=4,8*6,4*10^{20+(-12)}=30,72*10^{8}\\ 30,72*10^8 = 307,2*10^7\\ 307,2*10^7 - 5,02*10^7 = 302,18*10^7$