Question

Alguém sabe resolver isso?

Answer 1

Segue a resolução da questão.

Answer 2

1.
a) (3^2)^2 = 3^(2.2) = 3^4 = 81
b) 4^18:4^15 = 4^(18-15) = 4^3 = 64
c) 5^2.5^1 = 5^(2+1) = 5^3 = 125
d) 2^2.6^2 = (2*6)^2 = 12^12 = 144
e) 70^3:10^3 = (70:10)^3 = 7^3 = 343
f) (10^3)^2 = 10^(3.2) = 10^6 = 1000.000

2.
a) 32 = 2.2.2.2.2 = 2^5
b) 1/128 = 1/(2.2.2.2.2.2.2) = 1/(2^7) = 2^-7
c) raiz 16 = raiz (2.2.2.2) = raiz (2^4) = 2^2 = 4
d) 0,125 = 1/8 = 1/(2.2.2) = 1/(2^3) = 2^-3

3.
[(3^4)^3 : 3^9]^-2 = [3^(4.3) : 3^9]^-2 = [3^12 : 3^9]^-2 = [3^(12-9)]^-2

[3^3]^-2 = 9^-2 = (1/9)^2 = 1/81

4. (4^10 . 8^-3 . 16^-2)/32 = [(2^2)^10 . (2^3)^-3. (2^4)^-2]/32
(2^20 . 2^-9 . 2^-8)/32 = [2^(20-9-8)]/32 = (2^3)/32 = 8/32 = 1/4