Question

Alguem sabe por favor me ajude

Answer 1

Resposta:

$x=3$

Explicação passo a passo:

$log_{3} (\frac{x+3}{x-1} )=1\\\\Usando\ a\ propriedade\ logaritmica:\ log_{a} (b)=c\ \rightarrow \ b=a^{c} \\\\(\frac{x+3}{x-1} )=3^{1} \\\\\frac{x+3}{x-1} = 3\\\\\frac{x+3}{x-1}(x-1)=3(x-1)\\\\x+3=3x-3\\\\3x-3=x+3\\\\3x-x=3+3\\\\2x=6\\\\x=\frac{6}{2} \\\\x=3$