Question

alguém sabe? Me ajudem

Answer 1

Explicação passo a passo:

$a)~~\sqrt[3]{{7\over5}} ={\sqrt[3]{7} \over\sqrt[3]{5} }\\ \\\\ b)~~\sqrt{{7\over3}} ={\sqrt{7} \over\sqrt{3} }\\ \\\\ c)~~\sqrt[5]{{3^2\over2^3}} ={\sqrt[5]{3^2} \over\sqrt[5]{2^3} }\\ \\\\ d)~~\sqrt[8]{{2^4\over3^5}} ={\sqrt[8]{2^4} \over\sqrt[8]{3^5} }$