Question

alguém sabe como usar Bhaskara com dois números??
Ajuda pfvv​

Answer 1

Resposta:

S={-5,5}

Explicação passo-a-passo:

2x²-50=0

a=2, b=0 e c= -50

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~2x^{2}-0x-50=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=2{;}~b=0~e~c=-50\\\\\Delta=(b)^{2}-4(a)(c)=(0)^{2}-4(2)(-50)=0-(-400)=400\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(0)-\sqrt{400}}{2(2)}=\frac{0-20}{4}=\frac{-20}{4}=-5\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(0)+\sqrt{400}}{2(2)}=\frac{0+20}{4}=\frac{20}{4}=5\\\\S=\{-5,~5\}$