Question

Alguém por gentileza....resolve essa loucura!!!

a+b/a²b+2a+b/a²b-3a+b/a²b

Answer 1

$\dfrac{a+b}{a^2b}+\dfrac{2a+b}{a^2b}-\dfrac{3a+b}{a^2b}\\\\ = \dfrac{a+b+2a+b-\left(3a+b\right)}{a^2b}\\\\ = \dfrac{a+b+2a+b-3a-b}{a^2b} \\\\ = \dfrac{b}{a^2b}\\\\ =\dfrac{1}{a^2}$