Question

Alguém poderia me ajudar? Segue foto abaixo dos exercícios

Answer 1

$-1,-4,-7,-10,-13,-16,-19 \\ \frac{3}{4}, \frac{6}{7} , \frac{9}{10} , \frac{12}{13} , \frac{15}{16}, \frac{18}{19} , \frac{21}{22} \\ \sqrt[]{2} , 2, 2 \sqrt[]{2}, 4, 4 \sqrt[]{2}, 8, 8 \sqrt[]{2} \\ 2.5,4.10,8.20,16.40,32.80,64.160,128.320$

Answer 2

a) $1,4,7,10,13,16,19,\dots$

O termo geral é $a_n=1+3n$.

b) $\dfrac{3}{4},\dfrac{6}{7},\dfrac{9}{10},\dfrac{12}{13},\dfrac{15}{16},\dfrac{18}{19},\dfrac{21}{22},\dots$

O termo geral é $\dfrac{3+3n}{4+3n}$.

c) $\sqrt{2},2,2\sqrt{2},4,4\sqrt{2},8,8\sqrt{2},16,\dots$

O termo geral é $(\sqrt{2})^{n}$.

d) $2\cdot5=10$, $4\cdot10=40$, $8\cdot20=160$, $16\cdot40=640$, $\dots$

O termo geral é $10\cdot4^{n}$.

$10,40,160,640,2560,10240,40960$.