Question

alguém poderia me ajudar por favor?​

Answer 1

Explicação e resposta:

1a) $\sqrt{7}=x^{\frac{1}{2} }$

b) $\sqrt[4]{2^{3}} =2^{\frac{3}{4} }$

c) $\sqrt[5]{3^{2}}=3^{\frac{2}{5}}$

d) $\sqrt[6]{a^{5}}=a^{\frac{5}{6}}$

e) $\sqrt[3]{x^{2} } =x^{\frac{2}{3}}$

f) $\frac{1}{\sqrt{3}}=\frac{1}{3^\frac{1}{2}}=3^{-\frac{1}{3}}$

2a) $2^\frac{1}{5}=\sqrt[5]{2}$

b) $4^\frac{2}{3}=\sqrt[3]{4^2}$

c) $x^\frac{1}{4}=\sqrt[4]{x}$

d) $8^{-\frac{1}{2}}=\sqrt8^{-1}=\frac{1}{\sqrt{8}}$

e) $a^\frac{5}{7}=\sqrt[7]{a^{5}}$