Question

Alguém poderia me ajudar?

Answer 1

$2^(^x^+^3^) + 2^(^x^+^1^) = 5^(^y^+^3^) + 3.(5^y) \\\\\\ 2^x*2^3+2^x*2^1 = 5^y*5^3+3*5^y\\\\\\\ 8*2^x+2*2^x = 125*5^y+3*5^y$

$8*2^x+2*2^x = 125*5^y+3*5^y\\\\\\\ 10*2^x = 128*5^y\\\\\\ 5*2^(^x^+^1^) = 2^7*5^y$

$2^(^x^+^1^) = 2^7\\\\\\ (x+1) = 7\\\\\ \boxed{x=6}$

$5=5^y\\\\\ \boxed{y=1}$

$\therefore\ x-y = 6-1\\\\\ \boxed{x-y=5}$

Letra B.